Draw a table and find the thickness
Given: Thickness of a pile of
12 cardboards
=35 mm
Let the thickness of pile of
294 cardboards be
′x′ mm
Thickness (mm) |
35 |
x |
No. of cardboards |
12 |
294 |
Clearly, more the number of cardboards, more will be the thickness of pile of those cardboards. So, it is a case of direct variation.
Therefore, ratio of the thickness to the number of cardboards would be same for both the cases.
⇒3512=x294
⇒x=294×3512
⇒x=857.5
Thus, the thickness of pile is
857.5 mm or
85.75 cm
(∵1 cm=10 mm)
Hence, the thickness of a pile of
294 cardboards is
857.5 mm or
85.75 cm.
Verify using unitary method
Given: Thickness of a pile of
12 cardboards
=35 mm
⇒ Thickness of a pile of
1 cardboard
=3512 mm
⇒ Thickness of a pile of
294 cardboards
=3512×294
=857.5 mm
Thus, the thickness of pile is
857.5 mm or
85.75 cm
∵1 cm=10 mm
Hence, verified.