Sets A and B have 3 and 6 elements respectively. What can be the minimum number of elements in A UB

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Solution

The correct option is B
6

n(A $\cup$ B) = n(A) + n(B) - n(A $\cap B$ ) = 3 + 6 - 1 $(A \cap B)$

Since maximum number of elements in A $\cap$ B = 3

$∴$ Minimum number of elements in A $\cup$ B = 9 - 3 = 6 .

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