Sets A, B, C and D are all subsets of quadrilaterals. A is the set of rhombi, B is the set of rectangles, C is the set of parallelograms, and D is the set of kites. What is the set $(A \cap B) \cup (C \cap D)$ ?

squares

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rectangles

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parallelograms

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rhombi

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Solution

The correct option is D rhombi
Soln:

$A \cap B$ is a set of quadrilaterals that are both rhombi and rectangles - which are squares. $C \cap D$ is a set of quadrilaterals that are both parallelograms and kites - which are rhombi. Finally, the union of squares and rhombi are... rhombi. Hence option (d)

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