Seven capacitors each of capacitance 2μF are connected in a configuration to obtain an effective capacitance 1011μF. Which of the following combination will achieve the desired result?
A
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is A Two capacitors are conected in series, C=C1C2C1+C2=42+2=1μF
Five capacitors are connected in parallel, so Cp=5(2)=10μF
Effective capacitance is ∴Cnet=(10)(1)10+1=1011μF
hence (a) is correct.