Seven identical lamps of resistance 2200Ω each are connected to 220V line as shown in the figure. What will be the reading in the ammeter?
A
0.1A
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B
0.13A
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C
0.4A
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D
0.7A
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Solution
The correct option is C0.4A Let the left point of ammeter be B and right point be C . Then say the equivalent parallel resistance on left side be R1 and on right side be R2. R1=22004:R2=22003 So the current across ammeter will be the current across R1. Net current is I=220×72200=0.7A Thus current across ammeter would be , R2R2+R1×I=2200×42200×7×0.7=0.4A