1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# Seven persons sit in a row at random. The probability that three persons A,B and C sit in that order, not necessarily side by side, is

A
37!
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
B
7C37!
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
C
13!
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
17!
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
Open in App
Solution

## The correct option is A 13!Since our only concern is about A,B and C, we look at their permutations.The total number of ways they can sit irrespective of the other people is 3! number of ways.Given the constraint, for the same case of the other 4 people, A,B and C, have only 1 way to sit.So, for every case of desired permutation, there are 3! times more permutations in the universal set. So probability : 13!

Suggest Corrections
0
Join BYJU'S Learning Program
Related Videos
Independent and Dependent Events
MATHEMATICS
Watch in App
Explore more
Join BYJU'S Learning Program