Seven pulleys are connected with the help of 3 light strings as shown in the figure. Consider P3,P4,P5 as light pulleys and pulleys P6 and P7 have masses m each. For this arrangement mark the correct statement(s):
A
Tension in the string connecting P1,P3 and P4 is zero
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
Tension in the string connecting P1,P3 and P4 is mg3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
Tension in all the 3 strings are same and equal to zero
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
Acceleration of P6 is g downward and that of P7 is g upward
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct options are B Tension in the string connecting P1,P3 and P4 is zero D Tension in all the 3 strings are same and equal to zero
Let tension, in 3 strings be T1, T2 and T3 respectively For pulley P3:2T1−T1=0×a⇒T1=0 For pulley P4:2T1−T2=0⇒T2=0 For pulley P5:2T2−T3=0T2=T3=0