Seven resistors are connected as shown in the diagram-The equivalent resistance in - of this network between A and B is-A- 6B- 8C- 12D- 20

The correct option is A 6The given circuit is equivalent to As 10× 4=5× 8, therefore this is balanced Wheatstone network ⇒ R=(5+4)× (10+8)9+18=6 Ω ...

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Standard XII

Physics

Wheatstone Bridge

Seven resisto...

Question

Seven resistors are connected as shown in the diagram.

The equivalent resistance in $Ω$ of this network between $A$ and $B$ is:

6

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Solution

The correct option is A $6$
The given circuit is equivalent to

As $10 \times 4 = 5 \times 8$ , therefore this is balanced Wheatstone network
$\Rightarrow R = \frac{(5 + 4) \times (10 + 8)}{9 + 18} = 6 Ω$

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Seven resistors are connected as shown in the diagram. The equivalent resistance in Ω of this network between A and B is:

The correct option is A 6The given circuit is equivalent to As 10×4=5×8, therefore this is balanced Wheatstone network ⇒R=(5+4)×(10+8)9+18=6 Ω

Seven resistors are connected as shown in the diagram.

The equivalent resistance in $Ω$ of this network between $A$ and $B$ is:

The correct option is A $6$
The given circuit is equivalent to

As $10 \times 4 = 5 \times 8$ , therefore this is balanced Wheatstone network
$\Rightarrow R = \frac{(5 + 4) \times (10 + 8)}{9 + 18} = 6 Ω$