Seven times a given two digit number is equals to 4 times of the number obtained by interchanging the digits and the difference of digits is 3 find the number
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Solution
Let numbers be x at ones place and y at tens place so 10y+x is that digit now reversed digit is 10x+y according to question 7 (10y+x)=4(10x+y) x=2y (i) now given x-y=3 from eq. i 2y=x 2y-y=3 y=3 so x=63 required original no. is 36 and reversed digit is 63
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