Seven times a two digit number is equal to four times the number obtained by reversing the order of digits. Find the number, if the difference between its digits is $3$ .

14

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25

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36

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47

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Solution

The correct option is B $36$
Let one's digit be $x$ and the tens be $x - 3$

Number = $10 (x - 3) + x$

Reversed no. = $10 x + x - 3$

$7 (10 (x - 3) + x) = 4 (x - 3 + 10 x) 70 x - 210 + 7 x = 4 x - 12 + 40 x 33 x = 198 x = 6$

Number = $36$

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Seven times a two digit number is equal to four times the number obtained by reversing the order of its digits . if the difference of digits is 3, determine the number

Seven times a two digit number is equal to four times the number obtained by reversing the digits. If the difference between the digits is 3, find the number.

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Seven times a two digit number is equal to four times the number obtained by reversing the order of digits. Find the number, if the difference between its digits is 3.

The correct option is B 36Let one's digit be x and the tens be x−3Number = 10(x−3)+x Reversed no. = 10x+x−3 7(10(x−3)+x)=4(x−3+10x)70x−210+7x=4x−12+40x33x=198x=6 Number = 36

Seven times a two digit number is equal to four times the number obtained by reversing the order of digits. Find the number, if the difference between its digits is $3$ .

The correct option is B $36$
Let one's digit be $x$ and the tens be $x - 3$

Number = $10 (x - 3) + x$

Reversed no. = $10 x + x - 3$

$7 (10 (x - 3) + x) = 4 (x - 3 + 10 x) 70 x - 210 + 7 x = 4 x - 12 + 40 x 33 x = 198 x = 6$

Number = $36$