Seven times a two digit number is equal to four times the number obtained by reversing the order of its digits . if the difference of digits is 3, determine the number

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Solution

Let numbers be x at ones place and y at tens place so
10y+x is that digit
now reversed digit is 10x+y
according to question
7 (10y+x)=4(10x+y)
x=2y (i)
now
given
x-y=3
from eq. i 2y=x
2y-y=3
y=3
so
x=63
required original no. is 36 and reversed digit is 63

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Seven times a two digit number is equal to four times the number obtained by reversing the order of its digits . if the difference of digits is 3, determine the number

Let numbers be x at ones place and y at tens place so 10y+x is that digit now reversed digit is 10x+y according to question 7 (10y+x)=4(10x+y) x=2y (i) now given x-y=3 from eq. i 2y=x 2y-y=3 y=3 so x=63 required original no. is 36 and reversed digit is 63

Let numbers be x at ones place and y at tens place so
10y+x is that digit
now reversed digit is 10x+y
according to question
7 (10y+x)=4(10x+y)
x=2y (i)
now
given
x-y=3
from eq. i 2y=x
2y-y=3
y=3
so
x=63
required original no. is 36 and reversed digit is 63