Question

Several 10 pF capacitors are given, each capable of withstanding 100 V. How would you construct a circuit unit possessing a capacitance of 2 pF and capable of withstanding 500 V?

Answer 1

For the above requirement, Five capacitors in series will have

$C_{eq}=\frac{C}{5}=2pF$

Voltage capability =$5V_C=500V$