Question

${SF}_2,{SF}_4$ and ${SF}_6$ have the hybridisation of sulphur atom respectively as:

• A. ${sp}^2,{sp}^3,{sp}^3{d}^2$
• B. ${sp}^3,{sp}^3,{sp}^3{d}^2$
• C. ${sp}^3,{sp}^{3}d,{sp}^3{d}^2$
• D. ${sp}^3,{sp}^3{d}^2,d^2{sp}^3$

Answer 1

The correct option is C ${sp}^3,{sp}^{3}d,{sp}^3{d}^2$

No. of electron pair$=$ No.of atoms bonded to it $+1/2$ (Group number of central atom-valency of central atom)
${SF}_2=2+\frac{1}{2}(6-2)=4$
Hybridisation$={sp}^3$
${SF}_4=4+\frac{1}{2}(6-4)=5$
Hybridization $={sp}^{3}d$
${SF}_6=6+\frac{1}{2}(6-6)=6$
Hybridization $={sp}^3{d}^2$