Shane has to fill a water tank in 3 hours 40 minutes and he used 7 pipes for that. How many pipes should he use to fill the tank in 1 hour 21 minutes?

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Solution

Let the number of pipes be y.

$\begin{matrix} Number of pipes & 7 & y Time (in minutes) & 220 & 81 \end{matrix}$

The number of pipes and the time are inversely proportional.

AB = constant
$A_{1} \times B_{1}$ = $A_{2} \times B_{2}$

$7 \times 220 = y \times 81 \frac{7}{y} = \frac{81}{220}$

$\Rightarrow y = \frac{7 \times 220}{81} = 19.01 \approx 19$

Shane has to use 19 pipes to fill the tank in 1 hour 21 minutes.

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Shane has to fill a water tank in 3 hours 40 minutes and he used 7 pipes for that. How many pipes should he use to fill the tank in 1 hour 21 minutes?

Let the number of pipes be y. Number of pipes7yTime (in minutes)22081 The number of pipes and the time are inversely proportional. AB = constant A1×B1 = A2×B2 7×220=y×817y=81220 ⇒y=7×22081=19.01≈19 Shane has to use 19 pipes to fill the tank in 1 hour 21 minutes.