Question

Shanti sweets stall was placing an order for making cardboard boxes for packing their sweets, two sizes of boxes were required. The bigger of dimension $25cm$ $25cm\times 20cm\times 5cm$ and the smaller of dimensions $15cm\times 12cm\times 5cm$ for all the overlaps, $5\%$ of the total surface area is required extra. if the cost of the cardboard is INR 4 for 1000 $c{m}^2$, find the cost of cardboard required for supplying 250 boxes of each.

Answer 1

Dimension of bigger box $=25cm\times 20cm\times 5cm$

Total surface area of bigger box $=2(lb+bh+lh)$

$=2(25\times 20+20\times 5+25\times 5)$

$=1450c{m}^2$

Dimension of smaller box $=15cm\times 12cm\times 5cm$

Total surface area of smaller box $=2(lb+bh+lh)$

$=2(15\times 12+12\times 5+15\times 5)$

$=630c{m}^2$

Total surface area of $250$ boxes of each type $=250(1450+630)$ $=250\times 2080c{m}^2=520000c{m}^2$

Extra area required $=\frac{5}{100}(1450+630)\times 250c{m}^2=26000c{m}^2$

Total Cardboard required $=(520000+26000)c{m}^2=546000c{m}^2$

Total cost of cardboard sheet$=(546000\times \frac{4}{1000})=Rs.2184$