Sharon celebrated her $16^{t h}$ birthday $x$ years ago. How old would she be in $z$ years time ?

x - 16 + z

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16 + x - z

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16 + x + z

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16 - x + z

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Solution

The correct option is C $16 + x + z$
Since Sharon celebrated her $16^{t h}$ birthday $x$ years ago
Therefore her present age $= 16 + x$ years.
After $z$ years his age will be $z$ more than present age i.e $16 + x + z$ years.
Option $C$ is correct.

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x, y, z \in R

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$16 x^{2} + 4 y^{2} + 9 z^{2} - 16 x y - 12 y z + 24 x z$

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$4 x^{2} + 9 y^{2} + 16 z^{2} + 12 x y - 24 x y z - 16 z x$

Factorise: $4 x^{2} + 9 y^{2} + 16 z^{2} + 12 x y - 24 y z - 16 x z .$

Factorize: $9 x^{2} + 16 y^{2} + 4 z^{2} - 24 x y + 16 y z - 12 x z$

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