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Question

Shew that (a2+b2+c2)3+2(bc+ca+ab)33(a2+b2+c2)(bc+ca+ab)2=(a3+b3+c33abc)2.

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Solution

Let X=a2+b2+c2,Y=bc+ca+ab, Then

L.H.S. =X3+2Y33XY2=(XY)2(X+2Y)

=(XY)2(a+b+c)2={(XY)(a+b+c)}2

={(a+b+c)(a2+b2+c2abbcca)}2

=(a3+b3+c33abc)2=R.H.S.

Hence, proved.

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