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Question

Shew that (x+y)nxnyn is divisible by xy(x2+xy+y2), if n is an odd positive integer not a multiple of 3.

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Solution

The expression (x+y)nxnyn vanishes when x=0,y=0
Hence it is divisible by xy
x=wy, the expression =yn{(1+w)n1wn}
=yn{1+wn+(w2)n}
n being odd, the expression vanishes if n is not a multiple of 3
x=w2y the expression =yn{1+wn+(w2)n}
n3kx=w2y is a factor
xy(xwy)(xw2y)
xy(x2+y2+xy)

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