Ship A is located 4km north and 3km
east of ship B. Ship A has a velocity of 20km h−1 towards the south and ship B is moving at 40km h−1 in a direction 37∘ north of east. X and Y axes are along east and north directions, respectively
A
Velocity of A relative to B is −32^i−44^j
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B
Position of A relative to B as a function of time is given by →rAB=(3−32t)^i+(4−44t)^j
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C
Velocity of A relative to B is 32^i−44^j
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D
Position of A relative to B as a function of time is given by (32t^i−44t^j)
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Solution
The correct option is B Position of A relative to B as a function of time is given by →rAB=(3−32t)^i+(4−44t)^j
→vA=−20^jkmh−1 →vB=[(40cos37∘)^i+(40sin37∘)^j]kmh−1 =(32^i+24^j)kmh−1 →vAB=→vA−→vB =(−20^j)−(32^i+24^j) =−32^i−44^j
Option (a) is correct
Option (c) is incorrect
At any time →SA=3^i+4^j+(−20^j)t →SB=(32^i+24^j)t
Position of A relative to B: →SAB=→SA−→SB =(3^i+4^j−20t^j)−(32t^i+24t^j) =(3−32t)^i+(4−44t)^j
Option (b) is correct.
Option (d) is incorrect.