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Question

Ship A is located 4 km north and 3 km
east of ship B. Ship A has a velocity of 20 km h1 towards the south and ship B is moving at 40 km h1 in a direction 37 north of east. X and Y axes are along east and north directions, respectively

A
Velocity of A relative to B is 32^i44^j
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B
Position of A relative to B as a function of time is given by
rAB=(332t)^i+(444t)^j
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C
Velocity of A relative to B is 32^i44^j
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D
Position of A relative to B as a function of time is given by (32t^i44t^j)
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Solution

The correct option is B Position of A relative to B as a function of time is given by
rAB=(332t)^i+(444t)^j


vA=20^j kmh1
vB=[(40 cos 37)^i+(40 sin 37)^j] kmh1
=(32^i+24^j) kmh1
vAB=vAvB
=(20^j)(32^i+24^j)
=32^i44^j
Option (a) is correct
Option (c) is incorrect
At any time
SA=3^i+4^j+(20^j)t
SB=(32^i+24^j)t

Position of A relative to B:
SAB=SASB
=(3^i+4^j20t^j)(32t^i+24t^j)
=(332t)^i+(444t)^j
Option (b) is correct.
Option (d) is incorrect.

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