Ship A is travelling with a velocity of 5km h−1 due east. The second ship is heading 30∘ east of north. What should be the speed of second ship if it is to always remain due north with respect to the first ship?
A
10km h−1
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B
9km h−1
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C
8km h−1
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D
7km h−1
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Solution
The correct option is A10km h−1 For B always to be north of A, the velocity components of both along east should be same. Therefore, v2cos60∘=v1⇒v2=10km h−1