CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Show by a diagram how resistors R1,R2 and R3 are joined in parallel. Obtain an expression for the total resistance of the combination.
[5 MARKS]

Open in App
Solution

Circuit diagram: 2 Marks
Derivation: 3 Marks

In the parallel combination of resistors, one end of each resistor is connected at one point (say A) and the other end of each resistor is connected at the other point (Say B).
A cell is then connected in between these points A and B through a key as shown in Fig. 8.26.

Let R be the equivalent resistance, V be the potential difference applied between the ends A and B and I be the current that enters at A. Then the current I divides itself into three branches I1,I2 and I3 flowing through the resistors R1,R2 and R3 respectively.
Total current, I=I1+I2+I3 ...(i)
Potential difference between A and B,
V=I1R1=I2R2=I3R3
Or I1=VR1 , I2=VR2 ,and I3=VR3
As R is the equivalent resistance and I the total current,
I=VR
Substituting I=VR in Eq. (i), we get :
VR=VR1+VR2+VR3
Or 1R=1R1+1R2+1R3
Thus, when three or more resistors are connected in parallel, the reciprocal of the combined resistance is equal to the sum of the reciprocal of the individual resistances.

flag
Suggest Corrections
thumbs-up
6
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Series?
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon