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Hydrogenation of Alkynes

Show by means...

Question

Show by means of reactions, how you will inter-convert cis-trans isomers of hex-3-ene?

B r_{2} / C C l_{4}

;

2. N a N H_{2} / N H_{3}

L i n d l a r P d / C H_{2}

for cis;

L i, N H_{3}

for trans

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B r_{2} / C C l_{4}

;

2. N a N H_{2} / N H_{3}

L i n d l a r P d / C H_{2}

for trans;

L i, N H_{3}

for cis

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B r_{2} / C C l_{4}

;

2. N a N H_{2} / N H_{3}

L i n d l a r P d / C H_{2}

for trans;

N a, N H_{3}

for cis

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B r_{2} / C C l_{4}

;

2. N a N H_{2} / N H_{3}

L i n d l a r P d / C H_{2}

for cis;

N a, N H_{3}

for trans

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

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Solution

The correct option is D 1. $B r_{2} / C C l_{4}$ ; $2. N a N H_{2} / N H_{3}$ 3. $L i n d l a r P d / C H_{2}$ for cis; $N a, N H_{3}$ for trans
Start with any isomer and bromine addition across the double bond of hex-3-ene gives 3,4-dibromohexane.

From the above compound, get to hex-3-yne by dehydrohalogenation:

Getting to hex-3-yne is the key. From there it is easy!

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Similar questions

[C o (N H_{3}) C l (e n)_{2}]^{2 +}

Draw the cis and trans structures of hex-2-ene. Which isomer will have higher b.p. and why?

[C o (N H_{3})_{4} C l_{2}]^{+}

C i s - [C o (N H_{3})_{2} (e n)_{2}]^{3 +}

T r a n s - [I r C l_{2} (C_{2} O_{4})_{2}]^{3 -}

[R h (e n)_{3}]^{3 +}

c i s - [I r (H_{2} O)_{3} C l_{3}]

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