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Question

Show for positive number a, b, c bca+acb+abca+b+c

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Solution

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bca+acb2(abc2ab)12bca+acb2c...(i)

Similarly acb+abc2a...(ii)

abc+bca2b...(iii)

Now add (i), (ii) & (iii)

2(abc+bca+cab)2(a+b+c)

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