Show tha 4 sin 27 =(5+(5)) - (3-(5))

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4 sin 27^{\circ} = {(5 + \sqrt{5})}^{1 / 2} + {(3 - \sqrt{5})}^{1 / 2}

\sin \frac{π}{5} \sin \frac{2 π}{5} \sin \frac{3 π}{5} \sin \frac{4 π}{5} = \frac{5}{16}

Solve:

[[5×{(−3)×(−4)}]÷{27 + (−14−3)}][[3×{(−4)×(−5)}]÷{27+(−13−4)}]
+[{27×(−2)}÷(−3−3)] + [{27×(−2)}÷(−3−3)]
+[{(−3)×(−3)×5}÷(−3)]]

5 tan α

\frac{5 s i n α - 3 c o s α}{5 s i n α + 2 c o s α} = \frac{1}{6}

[3×[(-5)×(-4)]÷[27+(-13-4)]+[(27×(-2)]÷(-3-3)+[(-3)×(-3)×(-5)÷(-3)

Can you explain clearly

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