Show that $(- 2 + 5 x)$ is a factor of $34 x - 16 + 15 x^{2}$

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Solution

$\begin{matrix} 34 x - 16 = 15 x^{2} i f (- 2 + 5 x) i s f a c t o r o f a b o v e e q u a t i o n T h e n p u t, x = \frac{2}{5} a n d w e g e t V a l u e (0) 34 \times \frac{2}{5} - 16 + 15 \times \frac{4}{25} \frac{68}{5} - 16 + \frac{12}{5} \frac{80}{5} - 16 16 - 16 = 0 S o, (- 2 + 5 x) i s f a c t o r o f (34 x - 16 + 5 x^{2}) \end{matrix}$

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