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Question

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2sin1(35)tan1(1731)=π4

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Solution

L.H.S. =2sin1(35)tan1(1731)

=sin1(2×351925)tan1(1731)

=sin1(65×45)tan1(1731)

=sin1(2425)tan1(1731)

=tan1(247)tan1(1731)

=tan1(24717311+247×1731)

=tan1(744119217+408)

=tan1(625625)

=tan1(1)=π4= R.H.S.

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