Show that :
$(2 x + 5)^{2} - 20 x = (2 x - 5)^{2}$

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Solution

We have,
${(2 x + 5)}^{2} - 20 x = {(2 x - 5)}^{2}$
${(2 x)}^{2} + {(5)}^{2} + 2.2 x .5 - 20 x = {(2 x)}^{2} + {(5)}^{2} - 2.2 x .5$
$4 x^{2} + 25 + 20 x - 20 x = 4 x^{2} + 25 - 20 x$
We get $x = 0$

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Similar questions

Evaluate $(2 x + 5)^{2} - (2 x - 5)^{2}$

(2 x + 5)^{2} - (2 x - 5)^{2}

(2 x + 5)^{2} - (2 x - 5)^{2}

Question 4(ii)
Simplify:
$(2 x + 5)^{2} - (2 x - 5)^{2}$

Question 4(ii)
Simplify:
$(2 x + 5)^{2} - (2 x - 5)^{2}$

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