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Question

Show that (a, 1), (b, 1) and (c, 1) are collinear points

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Solution

(a, 1), (b, 1), (c, 1)
the slope between any two of these
points is m = 0
mab = (1-1)/(b-a) = 0
mac = (1-1)/(c-a) = 0
mbc = (1-1)/(c-b) = 0
This is a horizontal line. So long as
a, b, c are not equal ...
If a=b then (a, 1), (b, 1) are the same pont
If a=c then (a, 1), (c, 1) are the same point
If b=c then (b, 1), (c, 1) are the same point
If a=b=c then all three are actually the same point.
From the origin we go left or right a units and up 1
From the origin we go left or right b units and up 1
From the origin we go left or right c inits and up 1
Any two points with the same y value will
create a horizontal line of format y = c
where c is some number
In this case, (a, 1), (b, 1), (c, 1) are all on
the line y = 0x + 1 or y = 1

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