Show that any number of the form 6raise to x,XEN can never end with digit zero .
The prime factorisation of 6^x
= (2×3)^x
So it does contain a 2 in its prime factorisation but in this case a 5 is missing .
That means that it is not divisible by 2×5 both i.e. 10, So it is not possible for the number to end with a zero if its not divisible by 10.
This is the simple way to state that “ for any real number to end with zero its prime factorisation must contain 2×5 in it.”
So in your case the number 6^x will never end with zero for any natural value of 10