We have
Any positive integer is of the form 4q+1or4q+3
As per Euclid’s Division lemma.
If a and b are two positive integers, then,
a=bq+r
Where 0≤r<b.
Let positive integers be a.and b=4
Hence,a=bq+r
Where, (0≤r<4)
R is an integer greater than or equal to 0 and less than 4
Hence, r can be either 0,1,2and3
Now, If r=1
Then, our be equation is becomes
a=bq+r
a=4q+1
This will always be odd integer.
Now, If r=3
Then, our be equation is becomes
a=bq+r
a=4q+3
This will always be odd integer.
Hence proved.