Question

Show that $\cos {48}^{\circ }-\sin {42}^{\circ }=0$

Answer 1

$\cos 48°-\sin 42°=0$

$\Rightarrow L.H.S=\cos 48°-\sin 42°$

$=\cos (90°-42°)-\sin 42°$

$=\sin 42°-\sin 42°$

$=0$

$\Rightarrow L.H.S=R.H.S$

Hence, the answer is L.H.S=R.H.S