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Question

Show that : cos θ (tan θ + 2 ) (2 tan θ +1 ) = 2 sec θ + 5 sin θ

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Solution

L.H.S = cos θ (2 tan2 θ + 5 tan θ + 2 )

= cos θ [ 2 (tan2θ + 1 ) + 5 tanθ ]

= cos θ (2 sec2 θ + 5 tan θ ) = cos θ (2cos2θ+5sinθcosθ)

= 2secθ + 5 sin θ = R.H.S


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