Show that cosec- -cot- 2-1-cos-1-cos-

LHS=(cosecθ θ)^2=(1sinθ cosθsinθ)^2=(1 cosθ)^2sin^2 θ=(1 cosθ)^21 cos^2 θ=(1 cosθ)^2(1 cosθ)(1+cosθ)=1 cosθ1+cosθ=RHS ...

You visited us 2 times! Enjoying our articles? Unlock Full Access!

Trigonometric Ratios of Multiples of an Angle

Show that c...

Question

Show that $(c o s e c Θ - c o t Θ)^{2} = \frac{1 - c o s Θ}{1 + c o s Θ}$

Open in App

Solution

Suggest Corrections

Similar questions

{(c o s e c θ - c o t θ)}^{2} = \frac{1 - c o s θ}{1 + c o s θ}

\sqrt{\frac{1 + cos θ}{1 - cos θ}} = cosec θ + cot θ

(c o s e c θ - c o t θ)^{2} = \frac{(1 - c o s θ)}{(1 + c o s θ)}

$\frac{cos θ}{cosec θ + 1} + \frac{cos θ}{cosec θ - 1} =$ ___

{(c o s e c θ - c o t θ)}^{2} = \frac{1 - c o s θ}{1 + c o s θ}

\frac{c o s A}{1 + s i n A} + \frac{1 + s i n A}{c o s A} = 2 s e c A

Join BYJU'S Learning Program