Show that 1 A-tan A- A-tan A

→ 1 A+tan A = A tan A ^ 2 A tan^ 2 A = A tan A ...

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Sin(A+B)Sin(A-B)

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Question

Show that $\frac{1}{sec A + tan A} = sec A - tan A$

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Solution

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\frac{tan A}{1 - cot A} + \frac{cot A}{1 - tan A} = 1 + sec A c o s e c A

\frac{1}{sec A + tan A} - \frac{1}{cos A} = \frac{1}{cos A} - \frac{1}{sec A - tan A}

\frac{tan A}{1 - cot A} + \frac{cot A}{1 - tan A} = 1 + tan A + cot A

If tanA+1/tanA=2 show that tan²A +1/tan² A=2

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