Show that - 4ab-3cd2-4ab-3cd248-abcd

A] (4ab + 3cd)^2 (4ab 3cd)^2/48 = 16a^2b^2+9c^2+ 24abcd 16a^2b^2 9c^2d^2+24abcd/48 = 48abcd/48 = abcd Hence, proved. ...

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$\frac{(4 a b + 3 c d)^{2} - (4 a b - 3 c d)^{2}}{48} = a b c d$

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A B C D

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