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Byju's Answer
Standard XII
Mathematics
Permutation: n Different Things Taken r at a Time
Show that b...
Question
Show that
b
−
c
r
1
+
c
−
a
r
2
+
a
−
b
r
3
=
0
Open in App
Solution
LHS =
(
b
−
c
)
(
s
−
a
)
S
+
(
c
−
a
)
(
s
−
b
)
S
+
(
a
−
b
)
(
s
−
c
)
S
=
s
S
[
b
−
c
+
c
−
a
+
a
−
b
]
-
1
S
[
a
(
b
−
c
)
+
b
(
c
−
a
)
+
c
(
a
−
b
)
]
=
0
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0
Similar questions
Q.
Show that (
r
2
+
r
3
) / (1 + cos A) = (
r
3
+
r
1
) / (1 + cos B) = (
r
1
+
r
2
) / (1 + cos C).
Q.
In a triangle
A
B
C
,
, prove that
(
b
−
c
r
1
)
+
(
c
−
a
r
2
)
+
(
a
−
b
r
3
)
=
0
Q.
Assertion :In a
△
A
B
C
, if
a
<
b
<
c
and
r
is inradius and
r
1
,
r
2
,
r
3
are the axradii opposite to angle
A
,
B
,
C
respectively, then
r
<
r
1
<
r
2
<
r
3
Reason:
△
A
B
C
,
r
1
r
2
+
r
2
r
3
+
r
3
r
1
=
r
1
r
2
r
3
r
Q.
Prove
r
1
(
r
2
+
r
3
)
/
a
=
r
2
(
r
3
+
r
1
)
/
b
=
r
3
(
r
1
+
r
2
)
/
c
Q.
With usual notations, prove that in a triangle ABC
b
−
c
r
1
+
c
−
a
r
2
+
a
−
b
r
3
=
0
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Permutation: n Different Things Taken r at a Time
Standard XII Mathematics
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