Show that sin 2-sin 2-cos 2-cos- -

sin 2α #160; +sin 2β #160; #160; cos 2α #160; cos 2β #160; #160; = 2sin( 2α +2β #160; 2 #160; ) #160; cos( 2α 2β #160; 2 ...

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Arithmetic Mean

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Question

Show that $\frac{sin 2 α + sin 2 β}{cos 2 α - cos β} = cot (β - α)$

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\frac{sin 2 α + sin 2 β}{cos 2 α - cos 2 β} = cot (β - α)

α + β - γ = π

{sin}^{2} α + {sin}^{2} β - {sin}^{2} γ = 2 sin α sin β cos γ

cos α + cos β + cos α = 0 = sin α + sin β + sin α

{cos}^{2} α + {cos}^{2} β + {cos}^{2} α = \frac{3}{α} = {sin}^{2} α + {sin}^{2} β + {sin}^{2} α

α + β + Υ = π

{sin}^{2} α + {sin}^{2} β - {sin}^{2} Υ = 2 sin α sin β cos Υ

{cos}^{2} α + {cos}^{2} (α + β) - 2 cos α cos β cos (α + β) = {sin}^{2} β

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