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1+cosθ sin^2θsinθ(1+cosθ) =cosθ +cos^2θsinθ (1+cosθ) =cosθ(1+cosθ)sinθ(1+cosθ) =θ . ...

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Trigonometric Ratios of Multiples of an Angle

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Question

Show that:
$\frac{1 + cos θ - {sin}^{2} θ}{sin θ (1 + cos θ)} = cot θ .$

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\frac{1 + cosθ - \sin^{2} θ}{sinθ (1 + cosθ)} = cotθ

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