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Question

Show that dx(1+ex+e2x)=log{(z+12)+(z2+z+1)}. where z=1ex.

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Solution

Let I=exdxex(1+ex+e2x)
Put t=ex
dt=exdx
I=dtt1+t+t2
Now put t=1zdt=1z2dz
I=dz(z2+z+1)

=dz(z+12)2+(32)2
I=log{(z+12)+(z2+z+1)}+C where z=1t=1ex

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