Show that- 4-3 m - 3-4 n 2 - 2mn - 16-9 m2 - 9-16 n2

Onsider, CLHS = ( 4/3 m 3/4 n )^2 + 2mn = ( 4/3 m )^2 2 ( 4/3 m ) ( 3/4 n ) + ( 3/4 n )^2 + 2mn = 16/9 m^2 2mn + 9/16 n^2 + 2mn ...

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(a-b)^2 Expansion and Visualisation

Show that: ...

Question

Show that: ${(\frac{4}{3} m - \frac{3}{4} n)}^{2} + 2 m n = \frac{16}{9} m^{2} + \frac{9}{16} n^{2}$

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{(\frac{4}{3} m - \frac{3}{4} n)}^{2} + 2 m n = \frac{16}{9} m^{2} + \frac{9}{16} n^{2}

Question 5(iii)
Show that:
${(\frac{4}{3} m - \frac{3}{4} n)}^{2} + 2 m n = \frac{16}{9} m^{2} + \frac{9}{16} n^{2}$

Question 5(iii)
Show that:
${(\frac{4}{3} m - \frac{3}{4} n)}^{2} + 2 m n = \frac{16}{9} m^{2} + \frac{9}{16} n^{2}$

{(\frac{4}{3} m - \frac{3}{4} n)}^{2} + 2 m n = \frac{16}{9} m^{2} + \frac{9}{16} n^{2}

Show that

(i) (3x + 7)² − 84x = (3x − 7)²(ii) (9p − 5q)² + 180pq = (9p + 5q)²

(iii)

(iv) (4pq + 3q)²− (4pq − 3q)² = 48pq²

(v) (a − b) (a + b) + (b − c) (b + c) + (c − a) (c + a) = 0

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