![](https://byjus-answer-creation.s3.amazonaws.com/uploads/60e7df4424737982aa9fb83f_img_upload_solution_1646635968.png)
Let ABCD be a rectangle. Now, we know that every rectangle is also a parallelogram.
Consider ΔADB and ΔBCD
AD=BC [Opposite sides are equal]
AB=AB [Common base]
DB=AC [Diagonals of a rectangle are equal]
Therefore ΔADB≅ΔBCA by SSS rule.
Hence, ∠DAB=∠CBA [By CPCT]
But adjacent angles of a parallelogram are supplementary.
⇒∠DAB+∠CBA=180∘
⇒2∠DAB=180∘
∴∠DAB=∠CBA=90∘
Also, opposite sides of a parallelogram are equal, therefore, each angle id of 90∘ of rectangle ABCD.