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Question

Show that each of the following sequences is an A.P. Also find the common difference and write 3 more terms in each case.
(i) 3, −1, −5, −9 ...
(ii) −1, 1/4, 3/2, 11/4, ...
(iii) 2, 32, 52, 72, ...
(iv) 9, 7, 5, 3, ...

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Solution

(i) We have: -1-3 = -4,-5-(-1) = -4,-9-(-5) = -4...Thus, the sequence is an A.P. with the common difference being -4.The next three terms are as follows:-9-4 = -13-13-4 = -17-17-4 = -21(ii) We have:1/4-(-1) = 5/43/2-1/4 = 5/411/4-3/2 = 5/4Thus, the sequence is an A.P. with the common difference being (5/4).The next three terms are as follows:11/4+5/4 = 16/4 = 416/4+5/4 = 21/421/4+5/4 = 26/4

(iii) We have: 32 - 2 = 2252 - 32 = 2272 - 52 = 22Thus, the sequence is an A.P. with the common difference being (22).The next three terms are as follows:72+22 = 9292+22 = 112112+22 = 132(iv) We have: 7-9 = -25-7 = -23-5 = -2Thus, the sequence is an A.P. with the common difference being (-2).The next three terms are as follows:3-2 = 11-2 = -1-1-2 = -3

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