Show that 1- 2 - 1-cos- 1-cos- -1-

(1+cot^2θ)(1 cosθ)(1+cosθ)=(1+cos^2θ/sin^2θ)(1 cos^2θ) #160; #160; #160; #160; #160; #160; #160; #160; #160; #160; #160; #160; # ...

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Basic Trigonometric Identities

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Question

Show that $(1 + {cot}^{2} θ) (1 - cos θ) (1 + cos θ) = 1$ .

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(i) \sqrt{\frac{1 + \sin θ}{1 - \sin θ}} = (\sec θ + \tan θ) (ii) \sqrt{\frac{1 - \cos θ}{1 + \cos θ}} = (cosec θ - \cot θ) (iii) \sqrt{\frac{1 + \cos θ}{1 - \cos θ}} + \sqrt{\frac{1 - \cos θ}{1 + \cos θ}} = 2 cosec θ

\frac{1 - cosθ}{1 + cosθ} = (cosecθ - cotθ)^{2} .

(1 + {cot}^{2} θ) (1 - cos θ) (1 + cos θ) =

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