Show that- - - 1 - 2 i - 1- 3 i i 3 - 2- 1 - 3 - i - -7- 18 i- where i - - - 1 -

Given, [ 1 amp; 2i amp; 1; 3i amp;i^3 amp; 2; 1 amp; 3 amp; i ] =1·[ i^3 amp; 2; 3 amp; i ] ( 2i)[ 3i amp; 2; 1 a ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Properties of Iota

Show that: ...

Question

Show that: $∣ ∣ ∣ ∣ \begin{matrix} 1 & - 2 i & - 1 3 i & i^{3} & - 2 1 & - 3 & - i \end{matrix} ∣ ∣ ∣ ∣ = - 7 + 18 i$ , where $i = \sqrt{- 1}$ .

Open in App

Solution

Suggest Corrections

Similar questions

{(- 3 + 2 i)}^{2} - 3 (3 - i) (- 2 + 2 i)

i^{2} = - 1

a

∣ ∣ ∣ ∣ \begin{matrix} i & - 2 i & - 1 3 i & i^{3} & - 2 1 & - 3 & - i \end{matrix} ∣ ∣ ∣ ∣

a i

i = \sqrt{- 1}

A = ⎡ ⎢ ⎢ ⎢ ⎣ \begin{matrix} \frac{- 1 + i \sqrt{3}}{2 i} & \frac{- 1 - i \sqrt{3}}{2 i} \frac{1 + i \sqrt{3}}{2 i} & \frac{1 - i \sqrt{3}}{2 i} \end{matrix} ⎤ ⎥ ⎥ ⎥ ⎦, i = \sqrt{- i}

f (x) = x^{2} + 2

f (A)

| z_{1} - z_{2} |

z_{1}

z_{2}

| \sqrt{3} (1 - 2 z) + 2 i | = 2 \sqrt{7}

| \sqrt{3} (- 1 - z) - 2 i | = | \sqrt{3} (9 - z) + 18 i |

(14 + 2 i) (7 + 12 i)

i = \sqrt{- 1}

Join BYJU'S Learning Program