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Question

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(xaxb)ab.(xbxc)bc.(xcxa)c1=1

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Solution

L.H.S.(xaxb)ab.(xbxc)bc.(xcxa)c1=(xa+b)ab.(xb+c)bc.(xc+a)ca=x(a+b)(ab).x(b+c)(bc).x(c+a)(ca)=xa2b2+b2c2+c2a2=x0=1=R.H.S.


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