Show that - - a- -b- b- -c- c- -a- -2- a- b- c-

[ a + b b + c c + a #160; ] =( a + b #160; ) .[ ( b + c #160; ) ×( c + a #160; ) #160; ] =( a+b ) .[ ( b× c ) +( b× ...

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Composite Function

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Question

Show that : $[\to a + \to b \to b + \to c \to c + \to a] = 2 [\to a \to b \to c] .$

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Solution

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[\to a + \to b \to b + \to c \to c + \to a] = [\to a \to b \to c]

[\to a \to b \to c] = 4 t h e n [\to a \times \to b \to b \times \to c \to c \times \to a] =

[\to a + \to b \to b + \to c \to c + \to a] = 8

[\to a \to b \to c]

\to a, \to b

\to c,

[(\to a + \to b) (\to b + \to c) (\to c + \to a)] = 2 [\to a \to b \to c] .

[\begin{matrix} \to a + \to b & \to b + \to c & \to c + \to a \end{matrix}]

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