wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Show that limx0 sin 1x does not exist.

Open in App
Solution

limx0 sin 1xL.H.Llimx0- fxlimx0- sin 1xLet x=0-h where h0=limh0 sin -1h=-limh0 sin 1h

limx0- fx = – (An oscillating number that oscillates between –1 and 1)

Thus,limx0-fx does not exist.Similarly, limx0+fx does not exist.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Differentiating One Function wrt Other
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon