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Question

Show that m -1 is a factor of m21 - 1 and m22 - 1.

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Solution


Let p(m) = m21 − 1 and q(m) = m22 − 1.

Divisor = m − 1

Now,

p(1) = (1)21 − 1 = 1 − 1 = 0

Therefore, by factor theorem (m − 1) is a factor of p(m) = m21 − 1.

Also,

q(1) = (1)22 − 1 = 1 − 1 = 0

Therefore, by factor theorem (m − 1) is a factor of q(m) = m22 − 1.

Hence, (m − 1) is a factor of m21 − 1 and m22 − 1.

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