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Question

Show that (r2 + r3) / (1 + cos A) = (r3 + r1) / (1 + cos B) = (r1 + r2) / (1 + cos C).

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Solution

1+cosA= 2cos2A2=2s(sa)bc=Dr
r2+r3=Ssb+Ssc=Sa(sb)(sc)=Nr
T1=NrDr=SS2a(bc)2=abc2S
Hence, T1=T2=T3=abc2S by symmetry.

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