Question

Show that : ${\sec }^2\theta +cose{c}^2\theta ={\sec }^2\theta \times cose{c}^2\theta$.

Answer 1

${\sec }^2\theta +cose{c}^2\theta =\frac{1}{{\cos }^2\theta }+\frac{1}{{\sin }^2\theta }$

$=\frac{{\sin }^2\theta +{\cos }^2\theta }{{\sin }^2\theta {\cos }^2\theta }$

$=\frac{1}{{\sin }^2\theta {\cos }^2\theta }$

$={\sec }^2\theta \times cose{c}^2\theta$